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What is the gravitational force on a 987 kg satellite orbiting

5.1 × 10⁴ m above the surface of Earth? Assume the mass of Earth is
5.97 × 10²⁴ kg.

What is the gravitational force on a 987 kg satellite orbiting 5.1 × 10⁴ m above the-example-1

1 Answer

4 votes

Answer:

The gravitational force on the satellite can be calculated using the formula:

F = G * ((m1 * m2) / r^2)

Where:

F is the gravitational force

G is the gravitational constant (6.67 × 10^-11 N*m^2/kg^2)

m1 is the mass of the first object (in this case, the satellite)

m2 is the mass of the second object (in this case, Earth)

r is the distance between the two objects

Plugging in the given values, we have:

F = (6.67 × 10^-11 N*m^2/kg^2) * ((987 kg * 5.97 × 10²⁴ kg) / (5.1 × 10⁴ m)^2)

= 9.06 × 10^-6 N

Therefore, the gravitational force on the satellite is approximately 0.00000906 N.

Step-by-step explanation:

User Tariqul Islam
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