Question

if we toss two ballanced dice, and let A be the event that the sum of the face values of two dice is 8, and B be the event that the face value of the first one is 3.calculate P(A/B).

Answer 1

There are a total of 36 possible outcomes when you toss two dice. The event B, that the first die is a 3, has 3 successful outcomes: (3,1), (3,2), (3,3). The event A, that the sum of the dice is 8, has 3 successful outcomes: (3,5), (5,3), (4,4). Out of these 3 successful outcomes for event A, 2 of them are also successful outcomes for event B: (3,5) and (5,3). Therefore, the probability that event A occurs given that event B has already occurred is 2/3. In other words, P(A|B) = 2/3.

Step-by-step explanation: