Question

A current of 2 A flows for 10 h through a 100 Ω resistor. The energy consumed by the resistor is:

Answer 1

4 kWh

Step-by-step explanation:

When a current I flows through a resistor R, the power dissipated across the resistor is

P = I2R

For time t, the energy consumed by the resistor is,

E = Pt = I2Rt

Calculation:

Given that, current (I) = 2 A

Resistor (R) = 100 ohm

Time (t) = 10 hours

Energy consumed (E) = 22 × 100 × 10 = 4 kWh