Question

What’s the biggest and lowest number you can get with the number x^2+4x+3=0

Answer 1

Answer: The biggest number is x= -1 and

the lowest number is x= -3 .

Step-by-step explanation: Solution

or, x^2+4x+3=0

or, x^2+ ( 3+1 )x+3=0

or, x^2+3x + x +3=0

or, x (x + 3)+ 1(x + 3)=0

or, (x + 3) (x + 1)=0

Either,

(x + 3)= 0 , (x + 1)= 0

or, x= -3 , x= -1

Therefore, The biggest number is x= -1 and

the lowest number is x= -3 .

Answer 2

To find the solutions of the equation x^2+4x+3=0, you can use the quadratic formula:

x = (-b +/- sqrt(b^2 - 4ac)) / (2a)

where a, b, and c are the coefficients of the quadratic equation. In this case, a = 1, b = 4, and c = 3. Plugging these values into the formula gives:

x = (-4 +/- sqrt(16 - 413)) / (2*1)

x = (-4 +/- sqrt(4)) / 2

x = (-4 +/- 2) / 2

This means the two solutions for x are (-4 - 2) / 2 = -3 and (-4 + 2) / 2 = -1.

So the biggest and lowest numbers you can get with the number x^2+4x+3=0 are -3 and -1, respectively.