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SOMEONE PLEASE HELP PLS SOLVE ALL 4

SOMEONE PLEASE HELP PLS SOLVE ALL 4-example-1

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Answer:

(4.) 4(3 + 9)

(5.) 5(n + 7)

(6.) 7(11 + 3)

(7.) 8(5+n)

Explanation:

(4.) The area of a rectangle is length * width. Because there are two rectangles, the areas must be combined in order to find the total area.

The area of the first rectangle is 4*3 and the area of the second is 9*4 so the total area would be 4*3 + 4*9. We can factor out the 4 and simply add the 9 and 3 to get area = 4(3 + 9).

(5.) The total area before using the distributive property is 5 * n + 5 * 7. We factor out the 5 and add the n and 7 to get area = 5(n + 7)

(6.) We need two numbers whose product is 77 and two numbers whose product is 21. Also, one of the numbers must be the same (namely the width, since the width of both rectangles is equal and doesn't change).

We can use 7*11 for the first rectangle and 7*3 for the second rectangle. We factor out the 7 and add the 3 and 11 to get area = 7(3 + 11).

(7.) We need two numbers whose product is 5n and two numbers whose product is 40. Like number 6, the width of both rectangles must be the same. Since we already have 8 for the first rectangle, we can use 8 * n and 8 * 5.

We factor out the 8 and add the 5 and n to get 8(5 + n).

User Gregg B
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