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If f(x)=x^2 sin(2x), then dy/dx = ?​
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If f(x)=x^2 sin(2x), then dy/dx = ?​

User Ezra Siton
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1 Answer

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Given: f(x)=x^2 sin(2x)

Find: f’(x)

Using the product rule…

f’(x)=[(2x)(sin(2x))]+[(x^2)(cos(2x)•2)]

=> 2xsin(2x)+2x^2cos(2x)

Thus, f’(x)=2x^2cos(2x)+2xsin(2x)
User Ramit
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