Question

What is the KE of a 72.62 kg person running at 1.78 m/s

Answer 1

115 J (100 J if following significant rule)

Step-by-step explanation:

We can find the kinetic energy by applying the formula:

`\displaystyle{ \text{ KE} = (1)/(2)mv^2}`

m is mass and v is velocity. Therefore, substitute in the formula:

`\displaystyle{ \text{ KE} = (1)/(2) * 72.62 * {1.78}^(2) } \\ \\ \displaystyle{ \text{ KE} = (1)/(2) * 72.62 * 3.17} \\ \\ \displaystyle{ \text{ KE} \approx 115 \: \text{J}}`

If following the significant rule, it'd be 100 J but 115 J is more appropriate.