Answer:
2,213,722 J
Step-by-step explanation:
You want to know the work done by a 70 kg student running up a 3227 m hill.
Work
The work is the product of force and distance. The force is the product of mass and acceleration.
W = F·d = m·g·d
W = (70 kg)(9.8 m/s²)(3227 m) = 2,213,722 J
The student does 2,213,722 joules of work.
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Additional comment
1 kg·m²/s² = 1 J
We trust you can tell the difference between m representing mass, and m representing the unit meters. 'g' is the acceleration due to gravity. The value usually used in problems like this is 9.8. The accepted standard value is 9.80665. A value sometimes used when precision is not required is 10 m/s².