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With a mean of 3 inches with standard deviation of 0.03.

If the manufacturer intends to discard the bottom 2.87% and the top 3.59% of nails, in terms of their lengths, what would be the cut-off lengths for nails to be discarded?

Round your answers to
two decimal places.

Low-end: _______ inches

High-end: ______ inches

With a mean of 3 inches with standard deviation of 0.03. If the manufacturer intends-example-1
User Kakigoori
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1 Answer

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Answer:

To find the cut-off lengths for nails to be discarded, you can use the fact that the mean of the nail lengths is 3 inches, and the standard deviation is 0.03 inches.

The bottom 2.87% of the nails are the shortest 2.87% of the nails, and the top 3.59% of the nails are the longest 3.59% of the nails. You can use the normal distribution to find the number of standard deviations from the mean that the cut-off lengths are.

Since the manufacturer intends to discard the bottom 2.87% and the top 3.59% of nails, you can use the standard normal table to find that the cut-off lengths are -1.28 standard deviations from the mean for the bottom 2.87% and 1.28 standard deviations from the mean for the top 3.59%.

To find the cut-off lengths in inches, you can multiply the number of standard deviations by the standard deviation in inches:

Low-end: -1.28 * 0.03 inches/standard deviation = -0.0384 inches

High-end: 1.28 * 0.03 inches/standard deviation = 0.0384 inches

Rounded to two decimal places, the cut-off lengths are:

Low-end: -0.04 inches

High-end: 0.04 inches

So the manufacturer should discard nails that are shorter than

3 inches - 0.04 inches = 2.96

User Shivkumar
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