Question

(x, 5) and (9, 8); slope:1/4

Answer 1

`(\stackrel{x_1}{x}~,~\stackrel{y_1}{5})\qquad (\stackrel{x_2}{9}~,~\stackrel{y_2}{8}) \\\\\\ \stackrel{slope}{m}\implies \cfrac{\stackrel{\textit{\large rise}} {\stackrel{y_2}{8}-\stackrel{y1}{5}}}{\underset{\textit{\large run}} {\underset{x_2}{9}-\underset{x_1}{x}}} ~~ = ~~\stackrel{\stackrel{\textit{\small slope}}{\downarrow }}{\cfrac{1}{4}}\implies \cfrac{3}{9-x}=\cfrac{1}{4}\implies 12=9-x \\\\\\ 12+x=9\implies \boxed{x=-3}`