Question

3

An egg is thrown upward with an initial speed of 4 m/s. After 6
seconds, the egg's velocity is m/s

Answer 1

-56 m/s

Step-by-step explanation:

The projectile motion of velocity can be modelled as:

`\displaystyle{v = u + gt}`

u is initial velocity which is given in the problem (4 m/s), t is time which is also already given in the problem (6 seconds) and g is a constant of acceleration due to gravity (9.8 m/s²)

However, since the egg is thrown upward which is against the gravity direction, the sign of direction must be negative. Hence, g = - 9.8 m/s²

`\displaystyle{v = 4 - 9.8 * 6} \\ \\ \displaystyle{v = 4 - 60} \\ \\ \displaystyle{v = - 56 \: \text{m/s}}`