Question

An object with a mass of 3.3 kg experiences an applied force of 6.0 N and a frictional force of 0.8 N. What is it the resulting acceleration?

Answer 1

2.06ms^-2

Step-by-step explanation:

Fr = 0.8N, Fa = 6.0N, a = ?

Where Fr is the frictional force

" Fa is the Applied force

First you have to find the Net force(Fn)

Fn = Fr + Fa

Fn = 0.8 + 6.0

Fn = 6.8N

Fn = ma

Making acceleration subject of the formula

a = Fn/m

a = 6.8/3.3

a = 2.06060

therefore a = 2.06ms^-2