Question

Help me please, math is hard

Answer 1

see explanation

Explanation:

using the identity

sin²Θ = 1 - cos²Θ

consider the left side

1 -
`(sin^20)/(1+cos0)`

= 1 -
`(1-cos^20)/(1+cos0)`

1 - cos²Θ is a difference of squares and factors as (1 - cosΘ)(1 + cosΘ)

= 1 -
`((1-cos0)(1+cos0))/(1+cos0)` ← cancel (1 + cosΘ) on numerator/ denominator

= 1 - (1 - cosΘ) ← distribute parenthesis by - 1

= 1 - 1 + cosΘ

= cosΘ

= right side