Question

A. State the slope of the line containing

the points (4,-3) and (-9,6).
and (-9,6).
b. What is the slope of a line parallel to
this line?
c. What is the slope of a line
perpendicular to this line?

Answer 1

see explanation

Explanation:

calculate the slope m of the line using the slope formula

m =
`(y_(2)-y_(1) )/(x_(2)-x_(1) )`

with (x₁, y₁ ) = (4, - 3 ) and (x₂, y₂ ) = (- 9, 6 )

m =
`(6-(-3))/(-9-4)` =
`(6+3)/(-13)` = -
`(9)/(13)`

• Parallel lines have equal slopes.

Thus slope of a parallel line is m = -
`(9)/(13)`

given a line with slope m then the slope of a line perpendicular to it is

`m_(perpendicular)` = -
`(1)/(m)` = -
`(1)/(-(9)/(13) )` =
`(13)/(9)`