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Find the HCF and LCM of: -
y²-11y + 10, y² +9y-10, y ²-1

1 Answer

4 votes

Answer:

(y-1)

Explanation:

lets take the expression

1st expression: y²-11y+10

y²-10y-y+10

y(y-10)-1(y-10)

(y-10)(y-1)

2nd expression:y²+9y-10

y²+10y-y-10

y(y+10)-1(y+10)

(y+10)(y-1)

3rd expression:y²-1

(y-1)(y+1)

*HCF=(y-1)

*LCM=(y-1)(y+1)(y-10)(y+10)

(y²-1)(y²-10²)

User Evgeny Ruban
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