Question

Can someone answer all that's question....I really² need the answer ​

Answer 1

1.
In the triangle that contains x (call the other 2 angles as a and b, where a is the angle that is supplemetary to the center angle.)

a = 180 - 110 = 70 (supplemetary angles add up to 180)

b = 30 (b and the angle measures 30 are in the same segment.)

-> x = 180 - 70 - 30 = 80.

2. In triangle PRT, v = 180 - 40 - 70 = 70.

Since P,Q,S,T all lies on the circumference, PQST is a cyclic quadrilateral.

-> w = 180 - PQS = 180 - (180 - 70) = 70.

3.
i) A 1:2 scale means that all sides of P must be shortened by twice the lengths.

Since D is the only shape with the sides shortened from P, it's the correct option.

ii) A 1:1/2 scale means that all sides of P must be enlarged by twice the lengths.

Therefore, the measures of the sides become sqrt(20),6,4,6 (clockwise from diagonal), which is B.

4. Using the Pythagoras' theorem, we can find the hypotenuse PR :
`\sqrt{12^(2) + 5^(2) } = 13`

sin(x) = QP/PR = 5/13 = 0.385 (rounded to 3 d.p)
tan(y) = QP/QR = 5/12 = 0.417 (rounded to 3 d.p)