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What is (2,-2) and (8,1) in y=mx+b form

User MatthewJ
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1 Answer

6 votes

Answer:

Explanation:

these are two points on the given line.


y-y_(1)=(y_(2)-y_(1))/(x_(2)-x_(1)) (x-x_(1))\\y-(-2)=(1-(-2))/(8-1) (x-2)\\y+2=(1+2)/(7) (x-2)\\y+2=(3)/(7) (x-2)\\7y+14=3x-6\\7y=3x-6-14\\7y=3x-20\\y=(3)/(7) x-(20)/(7) \\which~is~of~the~form~y=mx+b\\where~m=(3)/(7) \\b=-(20)/(7)

User Korun
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