Answer:
Step-by-step explanation:
To create a Punnett square for this problem, we first need to know the genotypes of the two parents. Since we are given that the first parent is heterozygous tall and the second parent is homozygous tall, we can represent their genotypes as Tt and TT, respectively.
Here is the Punnett square for this cross:
T t
T TT Tt
Tt Tt tt
From the Punnett square, we can see that the genotype ratios are 1 TT : 2 Tt : 1 tt. The phenotype ratios are 3 tall : 1 short, since all of the offspring with the genotypes TT and Tt will have the tall phenotype (since tall is dominant).
So the genotype ratios are 1:2:1 and the phenotype ratios are 3:1.