Question

How many iodine atoms are in 2.45 mol of BaI2

Answer 1

2.95*10^24

Step-by-step explanation:

for every mole of something, there is about 6.022*10^23 of that something. So for every mole of BaI2, there would be 6.022*10^23 molecules of BaI2.

For 2.45 moles of BaI2, there would be 2.45 * 6.022*10^23 molecules of BaI2, or 1.475*10^24 molecules of BaI2.

Since there is 2 atoms of iodine per molecule of BaI2, there would be
2*1.475*10^24 atoms of iodine, which simplifies to 2.95*10^24 after rounding to 3 sig figs.