Question

Determine the quadratic function with a vertex as a minimum point located at (3, 4).

Oy=3(x-3)² + 4
y=-4(x-4)²-3
y=-(x − 3)² + 4
y= (2+4)²-3

Answer 1

Explanation:So, in the form of (W)(x+c)^2+n,

1. C shows where the symmetrical line will be. If it's (+) then its on the negative side of the coordinate vice versa
2. n shows how high is the maximum or minimum height of the graph
3. W affect the area of the graph and its pretty much not used in this question.

• So, we've come to a conclusion:
• Xminimum=3
• Yminimum=4
• So the base form of the graph that has a minimum point of (3,4) is (x-3)^2+4, therefote the answer is 3(x-3)^2+4=y=f(x) is correct.