Answer:
The molarity of the solution is 1.339 M and the molality is 2.48 m.
Step-by-step explanation:
To calculate the molarity of the solution, you first need to determine the number of moles of sugar present in the solution. To do this, you can use the formula:
moles = grams / molecular weight
For sugar (sucrose), the molecular weight is 342.3 g/mol. So, the number of moles of sugar present in the solution is:
moles = 46 g / 342.3 g/mol = 0.1339 moles
To calculate the molarity of the solution, you then need to divide the number of moles of solute (sugar) by the volume of the solvent (water) in liters. Since there are 100 ml of water in the solution, the volume of the solvent in liters is 0.100 L. So, the molarity of the solution is:
molarity = moles / liters = 0.1339 moles / 0.100 L = 1.339 M
To calculate the molality of the solution, you need to determine the number of moles of sugar present in the solution and the mass of the solvent (water) in kilograms. Since there are 46 grams of sugar in the solution, the mass of the solvent in kilograms is 100 g - 46 g = 54 g. The mass of the solvent in kilograms is therefore 0.054 kg. The molality of the solution is then calculated using the formula:
molality = moles / kilograms = 0.1339 moles / 0.054 kg = 2.48 m