Question

Does someone mind helping me with this problem? Thank you!

Answer 1

(2,7)

Explanation:

y - 3x = 1 can be written

y -3x + 3x = 3x + 1 Add 3x to both sides

y = 3x + 1 Substitute 3x + 1 for y into the second equation

2y -x = 12

2(3x +1) -x = 12 Distribute the 2

2(3x) + 2(1) -x = 12

6x + 2 -x = 12 Combine like terms

5x + 2 = 12 Subtract 2 from both sides

5x + 2 -2 = 12 - 2

5x = 10 Divide both sides by 5

`(5x)/(5)` =
`(10)/(5)`

x = 2

substitute 2 for x in the equation y = 3x + 1 to solve for y

y = 3(2) + 1

y = 6 + 1

y = 7

(2,7) is the solution.

Answer 2

(2,7)

Explanation:

Solution Given:

y-3x=1

y=1+3x....(1)

2y-x=12

Substituing value of y

2(1+3x)-x=12

opening bracket

2+6x-x=12

2+5x=12

5x=12-2

x=10/5

x=2

again substituing value of x in equation 1

y=1+3•2

y=1+6

y=7