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Which of the following inequalities has a solution set of x>4?

1. 6(x−1)<4(x+2)−10
2. 3(x+2)<7(x−2)+4
3. 5(x+1)>2(x−1)+3
4. 4(x+2)>5(x+3)−3
A florist is looking to make arrangements of red and white roses for bouquets. The flowers are priced so that she makes a profit of $1.25 per red rose and $1.00 per white rose in a bouquet. Her goal is to make at least $1000 from sales of these bouquets. Based on her available time and supplies of red and white roses, she is considering two possibilities: 130 bouquets of 4 red roses and 3 white roses each or 110 bouquets of 3 red roses and 5 white roses each. Will either of these possibilities turn the profit the florist is seeking? (1 point)
a. Neither possibility will turn the profit the florist is seeking.
b. Only the 110 bouquets of 3 red roses and 5 white roses each will turn the profit the florist is seeking.
c. Only the 130 bouquets of 4 red roses and 3 white roses each will turn the profit the florist is seeking.
d. Both possibilities will turn the profit the florist is seeking.

User OferM
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1 Answer

3 votes

Answer:
Q). x>4? A). 5(x+1)>2(x−1)+3


Will either of these possibilities turn the profit the florist is seeking? (1 point)

a. Neither possibility will turn the profit the florist is seeking.

Explanation:

The solution set for the inequality x>4 is all values of x that are greater than 4. Therefore, the correct answer to the first question is 3.

To answer the second question, we need to calculate the profit made from each of the two possibilities. For the 130 bouquets of 4 red roses and 3 white roses each, the florist will make a profit of $1.254 + $1.003 = $5.50 per bouquet. Therefore, the total profit from this possibility will be $5.50*130 = $715.

For the 110 bouquets of 3 red roses and 5 white roses each, the florist will make a profit of $1.253 + $1.005 = $6.25 per bouquet. Therefore, the total profit from this possibility will be $6.25*110 = $687.50.

Since neither of these possibilities will turn a profit of $1000, the correct answer is a.

User Benedict Lewis
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