Question

A skydiver at rest jumps out of an airplane at 4, 000 meters. How fast will they be traveling in meters per second after 4 seconds?

Answer 1

Below

Step-by-step explanation:

v = at a = 9.81 m/s^2

v = 9.81 * 4 = 39.2 m/s after 4 secs

( Note that 4000 m height is not needed)