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Please help if can, thank you ;)

Please help if can, thank you ;)-example-1
User DaGUY
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the anoxia 50.24 had a test with this question
User Brimby
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Answer:

50.24 unit²

Explanation:

We know that,


\sf{Area\:of\:circle = \pi r^2}

Because a semicircle is half of a circle, its area is also half of a circle.


\sf{Area\:of\:semicircle = (1)/(2) \pi r^2}

Now, the given shape is one-fourth of a circle, which is called a quadrant. Therefore,


\sf{Area\:of\:quadrant= (1)/(4) \pi r^2}

Given that,

  • The radius of the quadrant = 8

Substituting the values into the formula we get,


\sf{\implies Area\:of\:quadrant= (1)/(4) \pi r^2}


\sf{\implies Area\:of\:quadrant= (1)/(4) * 3.14 * 8^2}


\sf{\implies Area\:of\:quadrant= (1)/(4) * 3.14 * 64}


\sf{\implies Area\:of\:quadrant= \frac{1}{\cancel{4}} * \cancel{200.96}}


\sf{\implies Area\:of\:quadrant= 1 * 50.24}


\sf{\implies Area\:of\:quadrant=50.24\:unit^2}

Therefore,


\sf{\boxed{\sf{50.24}}\:unit^2}

User Jkondratowicz
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