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On a roadway with two 12-ft lanes, a horizontal curve is designed for 35 mi/h with a 4% superelevation. It is known that A = 24. The PI of the curve is at station 30 + 00. What is the station of the PT of the curve?

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Answer:

In order to determine the station of the PT (point of tangency) of the horizontal curve, you will need to use the following formula:

PT = PI - (A / 100) x L

Where:

PT is the station of the PT of the curve

PI is the station of the PI (point of intersection) of the curve

A is the superelevation (expressed as a percentage)

L is the length of the curve

Using this formula, we can plug in the values given in the question to determine the station of the PT of the curve:

PT = 30 + 00 - (24 / 100) x L

Since the superelevation is 4% and the curve is designed for a speed of 35 mi/h, we can use the following formula to determine the length of the curve:

L = (V^2) / (R x f)

Where:

L is the length of the curve

V is the design speed (in mi/h)

R is the curve radius (in feet)

f is a factor that depends on the superelevation and the width of the roadway (expressed as a percentage)

For a 4% superelevation and a roadway with two 12-ft lanes, the value of f is approximately 0.15.

Using this formula, we can plug in the values given in the question to determine the length of the curve:

L = (35^2) / (R x 0.15)

If we assume that the curve radius is 1,000 feet (which is a common value for horizontal curves), we can solve for L to get:

L = (35^2) / (1000 x 0.15)

L = 338.88 feet

Now that we know the length of the curve, we can substitute this value into the first formula to determine the station of the PT of the curve:

PT = 30 + 00 - (24 / 100) x 338.88

PT = 30 - 8.19

PT = 21.81

Therefore, the station of the PT of the curve is approximately 21.81.

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