167k views
3 votes
The ice and steam points of an ungraduated thermometer are found to be 192mm apart. Calculate the length of the thermometric liquid above the ice point which will corresond to a temperature of 75 degree Celsius ​

User Mattt
by
7.5k points

1 Answer

4 votes

Answer:

To find the length of the thermometric liquid above the ice point that corresponds to a temperature of 75 degrees Celsius, we need to know the size of the temperature interval between the ice point and the steam point, as well as the size of the temperature interval between the ice point and 75 degrees Celsius.

The size of the temperature interval between the ice point and the steam point can be calculated using the formula:

T = (S - I)/R

Where T is the size of the temperature interval, S is the length of the thermometric liquid above the steam point, I is the length of the thermometric liquid above the ice point, and R is the size of the temperature interval per unit length of the thermometric liquid.

Since the ice and steam points of the thermometer are 192mm apart, we know that S - I = 192mm. We also need to know the value of R in order to calculate T.

Once we know the size of the temperature interval between the ice point and the steam point, we can use this value to calculate the size of the temperature interval between the ice point and 75 degrees Celsius.

Let's assume that the size of the temperature interval per unit length of the thermometric liquid, R, is 0.5 degrees Celsius per millimeter. With this value of R, the size of the temperature interval between the ice point and the steam point can be calculated as follows:

T = (192mm - 0mm)/0.5 degrees Celsius/mm = 384 degrees Celsius

Now that we know the size of the temperature interval between the ice point and the steam point, we can use this value to calculate the size of the temperature interval between the ice point and 75 degrees Celsius.

The size of the temperature interval between the ice point and 75 degrees Celsius is 75 degrees Celsius - 0 degrees Celsius = 75 degrees Celsius.

We can now use the size of the temperature interval between the ice point and 75 degrees Celsius, along with the size of the temperature interval per unit length of the thermometric liquid, R, to calculate the length of the thermometric liquid above the ice point that corresponds to a temperature of 75 degrees Celsius:

I = (75 degrees Celsius)/(0.5 degrees Celsius/mm) = 150mm

Thus, the length of the thermometric liquid above the ice point that corresponds to a temperature of 75 degrees Celsius is 150mm.

User AFRC
by
7.3k points