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On a coordinate plane, a curved line with a minimum value of (0.8, negative 11.4) and maximum values of (negative 1.6, 56) and (2, 0), crosses the x-axis at (negative 2.5, 0), (0, 0), and (2, 0), and crosses the y-axis at (0, 0).

What is the local maximum over the interval [–3, 1.5] for the graphed function?

0
56
–11.4
2

User Studog
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2 Answers

0 votes

Answer:

c

Explanation:

edge 23

User King Roger
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3 votes

Answer:

It is not possible to determine the local maximum of the graphed function over the interval [-3, 1.5] based on the given information. The maximum value of the curved line occurs at (negative 1.6, 56) and (2, 0), but these points do not fall within the interval [-3, 1.5]. Similarly, the minimum value of the curved line occurs at (0.8, negative 11.4), but this point also does not fall within the interval [-3, 1.5]. The curve crosses the x-axis and y-axis at (negative 2.5, 0), (0, 0), and (2, 0), but these points do not correspond to local maxima or minima of the curve.

To determine the local maximum over the interval [-3, 1.5], it would be necessary to have additional information about the shape of the curve and its values at points within the given interval.

Explanation:

User Roplacebo
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