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The sum of 5 consecutive odd numbers is 145.
What is the third number in this sequence?

User Martinos
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Answer: 29

Work Shown:

  • x = first odd number
  • x+2 = second odd number
  • x+4 = third odd number
  • x+6 = fourth odd number
  • x+8 = fifth odd number

Add up those items to get a sum of 145. Solve for x.

(x)+(x+2)+(x+4)+(x+6)+(x+8) = 145

5x+20 = 145

5x = 145-20

5x = 125

x = 125/5

x = 25

Then we can determine the following

  • 1st number = x = 25
  • 2nd number = x+2 = 25+2 = 27
  • 3rd number = x+4 = 25+4 = 29 is the answer
  • 4th number = x+6 = 25+6 = 31
  • 5th number = x+8 = 25+8 = 33

In short the sequence of numbers is: 25, 27, 29, 31, 33

As verification,

25+27+29+31+33 = 145

which tells us the answer is correct.

User John Morris
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