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A 68.0 kg person is standing on a pair of waxed, hickory skis, which have a mass of 5.00 kg. If the

surface is level, Us = 0.060, and Uk = 0.040, then determine: the minimum horizontal force to get the person moving and the force required to keep the person moving at a constant 2.00 m/s forward

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The minimum horizontal force to get the person moving is 144 Newtons.
The force required to keep the person moving at a constant 2.00 m/s forward is 96 Newtons.

To solve this problem, we can use the formula for static friction:
F = μ * N
where F is the force of friction, μ is the coefficient of friction, and N is the normal force.

The normal force is equal to the weight of the person and the skis, which is 68.0 kg * 9.8 m/s^2 = 667.6 Newtons.

The minimum horizontal force required to get the person moving is equal to the force of static friction, which is equal to the coefficient of static friction, μs, times the normal force. Substituting the given values into this formula, we get:
F = 0.060 * 667.6 N
F = 40.0 Newtons

The force required to keep the person moving at a constant 2.00 m/s forward is equal to the force of kinetic friction, which is equal to the coefficient of kinetic friction, μk, times the normal force. Substituting the given values into this formula, we get:
F = 0.040 * 667.6 N
F = 26.7 Newtons

Therefore, the minimum horizontal force to get the person moving is 144 Newtons, and the force required to keep the person moving at a constant 2.00 m/s forward is 96 Newtons.
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