Question

Does someone mind helping me with this problem? Thank you!

Answer 1

Answer is (2, -4)

Step by step

The question says to use SUBSTITUTION method where you substitute one equation into the other equation and solve

EQ # 1) x + 2y = -6
EQ # 2) 6x + 2y = 4

First I will change EQ #1 so just the x is on one side so I can substitute the value of x. Subtract 2y from both sides, now you have

EQ # 1) x = -2y -6
EQ #2) 6x + 2y = 4

Take value of x from EQ #1 and substitute into EQ #2.

6 (-2y -6) + 2y = 4
Distribute multiply

-12y -36 +2y = 4
Combine

-10y -36 = 4
Add 36 to both sides to isolate variable

-10y -36 +36 = 4 + 36
Combine

-10y = 40
Divide both sides by -10 to solve

-10/-10y = 40/-10

y = -4

Now substitute value of y into EQ #1

x = -2(-4) -6
Distribute multiply

x = 8 -6

x = 2

Check your work, substitute x and y into
EQ # 1)

2 = -2(-4) -6

2 = 2

It equals so solution is correct!

Answer 2

(2, -4)

Explanation:

-x - 2y = 6

6x + 2y = 4

-------------------

5x =. 10

x = 2

Now substitute to find y.

x + 2y = -6

2 + 2y = -6

2y = -8

y = -4