We need to find the point given the domain and range of the relation:
For domain and range, the result includes the number. Hence, the end values are given by the points.
For point C:
(-6,4)
Because point c is on quadrant two, where x is negative and y is positive.
Also, it takes the higher y value.
For point D:
(6,3)
Because point D is on quadrant 1, where x is positive and y is also positive.