Question

A rectangular swimming pool with a length of 18 meters and a width of 6 meters is surrounded by a concrete patio. The patio is a uniform 3 meters width around the entire pool. What is the area of the patio?

Answer 1

The area of the combined patio and swimming pool is

`\begin{gathered} (18\text{ m}+3\text{ m})(6\text{ m}+3\text{ m}) \\ =(21\text{ m})(9\text{ m}) \\ =189\text{ m}^2 \end{gathered}`

The area of the swimming pool is

`(18\text{ m})(6\text{ m})=108\text{ m}^2`

Subtract the combined area to the area of the swimming pool and we get

`189\text{ m}^2-108\text{ m}^2=81\text{ m}^2`

Therefore, the area of the patio is 81 square meters.