Answer:
x = 36
Explanation:
You want to know how many more 3-digit codes can be made from odd numbers than from even numbers if 0 is excluded and no digit can be repeated.
Code count
The number of possible codes will be the product of the number of available digits for each position in the code.
There are 5 odd digits, so Ali has 5 available digits for the first position, 4 for the next, and 3 for the last. (Using a digit makes it unavailable for a different position.) Ali can make 5·4·3 = 60 codes
There are 4 even digits when 0 is excluded, so Mel has 4 available digits for the first position, 3 for the next, and 2 for the last. Mel can make 4·3·2 = 24 codes.
Difference
Ali can make x more codes than Mel, where ...
x = 60 -24 = 36