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The equation of a circle with center (1,1) and radius 2 is given by

1 Answer

3 votes

Answer:

General form
x^(2) +
y^(2) -2x -2t -14 = 0

Explanation:


\sqrt{(x-1)^(2) +(y-1)^(2) } = 4 Square both sides


(x-1)^(2) +
(y-1)^(2) =
4^(2)


x^(2) - 2x + 1 +
y^(2) -2y + 1 = 16 Combine like terms


x^(2) +
y^(2) -2x - 2y +2 = 16 Subtract 16 from both sides


x^(2) +
y^(2) -2x -2y -14 = 0

User Henri Kerola
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