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Solve algebraically for X.
3600 + 1.02x < 2000 + 1.04x

1 Answer

3 votes

Answer:

x < -80000.

Explanation:

To solve the inequality 3600 + 1.02x < 2000 + 1.04x algebraically for x, you can start by subtracting 2000 + 1.04x from both sides of the inequality:

3600 + 1.02x - (2000 + 1.04x) < 2000 + 1.04x - (2000 + 1.04x)

1600 - 0.02x < 0

Then, you can divide both sides of the inequality by -0.02 to solve for x:

1600/-0.02 > 0/-0.02

-80,000 > x

The solution to the inequality is x < -80000.

You can check your solution by substituting -80000 into the original inequality:

3600 + 1.02(-80000) < 2000 + 1.04(-80000)

3600 - 81600 < 2000 - 832000

-45600 < -812000

Since -45600 is less than -812000, the solution x < -80000 is correct.

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