Answer:
Explanation:
To find the local maxima and minima, we need to find the points where the first derivative of the function is equal to zero. To find the inflection points, we need to find the points where the second derivative is equal to zero.
The first derivative of the function is given by:
f'(x) = 12x^3 + 12x^2 - 240x
To find the values of x for which the first derivative is equal to zero, we can set f'(x) equal to zero and solve for x:
12x^3 + 12x^2 - 240x = 0
This equation can be factored as:
(4x - 10)(3x^2 + 2x) = 0
This equation has three solutions: x = 10/4, x = 0, and x = -2/3.
To find the inflection points, we need to find the values of x for which the second derivative is equal to zero. The second derivative is given by:
f''(x) = 36x^2 + 24x - 240
To find the values of x for which the second derivative is equal to zero, we can set f''(x) equal to zero and solve for x:
36x^2 + 24x - 240 = 0
This equation can be factored as:
(6x + 40)(6x - 6) = 0
This equation has two solutions: x = -40/6 and x = 6/6.
Therefore, the function has local maxima and minima at x = 10/4 and x = -2/3, and inflection points at x = -40/6 and x = 6/6.