Question

If 120% of a is equal to 80% of b, then what is the value of a+b? PLEASE HELP ME SOLVE THISSSSS

Answer 1

Sure! I'd be happy to help you solve this problem.

First, let's rearrange the given equation to solve for the value of a:

120% of a = 80% of b

This can be rewritten as:

120/100 * a = 80/100 * b

Simplifying the right side of the equation, we get:

120/100 * a = 4/5 * b

Then, we can simplify the left side of the equation by canceling out the 100/100, which gives us:

120/100 * a = 4/5 * b

1/100 * a = 4/500 * b

a/100 = b/500

Next, we can multiply both sides of the equation by 100*500 to get rid of the fractions:

a = b/500 * 100*500

= b * 100

So now we know that a = 100 * b.

To find the value of a+b, we can substitute the expression for a into the equation:

a+b = (100b) + b

= 101b

Therefore, the value of a+b is equal to 101 times the value of b.

I hope this helps! Let me know if you have any questions or if you'd like to see any additional examples.

Explanation:

Answer 2

120/100 x a = 80/100 x b

Multiply both sides by 100 we get;

120 x a = 0 x b

Divide both sides by 80. We have

120/80a = 0 x b

120/80a = b

3/2a = b

We have to find the value of a+b in terms of a and b:

a + b = a + 3/2a

Combine like terms:

a + b = 5/2a

Now, find the value of a+b in terms of b;

Substitute equation [2] we have;

a + b = 2/3b + b

a + b = 5/3 b

So, the answer for the image is:

a + b = 5/2a

a + b = 5/3b