Question

What is the concentration of a solution made by diluting 65 mL of 6.0 M HCI to a final volume of 750 mL? Concentration: ____________ M

Answer 1

The concentration of the HCl solution after diluting 65 mL of a 6.0 M solution to a final volume of 750 mL is 0.52 M.

Step-by-step explanation:

The question asks about the concentration of a solution after dilution. The original concentration of HCl is 6.0 M (molar), and the initial volume is 65 mL. After dilution, the final volume of the solution is 750 mL. To calculate the concentration after dilution, we can use the formula:

C1V1 = C2V2

Where C1 and V1 are the initial concentration and volume, and C2 and V2 are the final concentration and volume. Plugging in the known values:

6.0 M × 0.065 L = C2 × 0.750 L

This simplifies to:

C2 = (6.0 M × 0.065 L) / 0.750 L = 0.52 M

So, the final concentration of the HCl solution is 0.52 M after dilution.

Answer 2

To solve this problem, we have to use the following formula:

`C1\cdot V1=C2\cdot V2`

In this case, C1 is 6.0M, V1 is 65ml and V2 is 750ml, use these values to find C2:

`\begin{gathered} C2=(C1V1)/(V2) \\ C2=(6.0M\cdot65ml)/(750ml) \\ C2=0.52M \end{gathered}`

The final concentration is 0.52M.