82.1k views
5 votes
Robyn adopted a child who is exactly 28 years younger than her.

In one year's time, Robyn will be 3 times as old as her child will be.
How old is Robyn now?

2 Answers

4 votes

Answer:

Robyn is 41years

Explanation:

let's represent Robyn age as x

so Robyn=x

child=x-28

In a year time

Robyn=x+1

child=x-28+1 =x-27

"Robyn will be three times as old as her child"

here multiply 3 by the child's age

child=3(x-27)

=3x-81

hence,x-1=3x-81. (group like terms)

x-3x=(-81-1)

-2x=-82 (divide both side by -2)

x=-82/-2

x=41

Therefore Robyn's age is 41

User Roy Dictus
by
8.2k points
6 votes

Answer:

Robyn is 41

Explanation:

You want to know Robyn's current age if she will be 3 times as old as her 28-year younger daughter in one year from now.

Ratio units

The difference in ages remains constant. When Robyn is 3 times as old as her daughter, the ratio of their ages is ...

Robyn : daughter = 3 : 1

The difference in their ages is 3 -1 = 2 ratio units. Each ratio unit stands for 28/2 = 14 years, so Robyn's age of 3 ratio units represents 42 years.

That will be 1 year from now, so Robyn is 41.

User Paxwell
by
8.2k points
Welcome to QAmmunity.org, where you can ask questions and receive answers from other members of our community.

9.4m questions

12.2m answers

Categories