Question

X=square root of 880-8x

Answer 1

`x=√(880-8x)\\ D:880-8x\geq0 \wedge x\geq0\\ D:8x\leq880 \wedge x\geq0\\ D:x\leq 110 \wedge x\geq0\\ D:x\in\langle0,110\rangle\\ x^2=880-8x\\ x^2+8x-880=0\\ x^2+8x+16-896=0\\ (x+4)^2=896\\ x+4=8√(14) \vee x+4=-8√(14)\\ x=-4+8√(14) \vee x=-4-8√(14)\\ \\ x=-4-8√(14)\\ot \in D \Rightarrow \boxed{x=-4+8√(14)}`