Answer:
The number of different passwords possible are:
5040
Explanation:
It is given that:
Geraldine is picking a four-digit password by using the digits 0 through 9.
Also she has to use each digit just once.
Hence, the number of such passwords possible are:
10×9×8×7=5040
( Since for the first place we have 10 choices as any of the digit 0-9 could come.
Also, for the second place we will have 9 choices as the number which came at the first place can't be placed again at the second.
Similarly for the third place we have 8 choices as the number which came in the first and second place is not be repeated
and for the fourth place any of the remaining 7 numbers could come up)