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every evening jenna empties her pockets and puts her change in a jar. At the end of the week she counts her money. One week she had 40 coins, all of them dimes and quarters when she added them she had a total of $7.75 let d= number of dimes and q = the number of quarters. How many quarters did she have?

2 Answers

5 votes

FOR PLATO ONLY

Solving Problems with Systems of Linear Equations: Mastery Test

Given:

40 coins = $7.75

x [ Number Of Dimes ] 10c

y [ Number Of Quarters ] 25c

Looking It UP Every Things Points to

[ Number Of Dimes ] 15(10) x = 1.50

[ Number Of Quarters ] 25(25) y = 6.25

So You'd Think 25 is Correct But No.. SEE ATTACHMENT

How Many Quarters Does She Really Have?

x [ Number Of Dimes ] 10c

y [ Number Of Quarters ] 25c

25y - 10x

x = 3.00 [ Number Of Dimes ]

y = 3.75 [ Number Of Quarters ]

FOR PLATO USERS THE ANSWER IS SIMPLY

15 Quarters :)


every evening jenna empties her pockets and puts her change in a jar. At the end of-example-1
every evening jenna empties her pockets and puts her change in a jar. At the end of-example-2
User Bruno Wego
by
7.6k points
2 votes
25 quaters
If you multiply .25*25+.10*15=7.75
......................
User Jahn
by
7.2k points