273,199 views
21 votes
21 votes
What number can be divided into 2 and 9 equal groups without a remainder

User Giesburts
by
2.9k points

1 Answer

25 votes
25 votes

One way to determine the number is to multiply 2 and 9, this is because the resulting number will be divisible by them perfectly. Let's try:


2\cdot9=18

So our candidate is 18, we need to test if it's divisible by 2 and 9 perfectly:


\begin{gathered} (18)/(2)=9 \\ (18)/(9)=2 \end{gathered}

It is, therefore the number is 18.

User Jeff Ogata
by
2.3k points
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