Question

4x(xy+2y^2-3y)-2y^2(2x^2+4xy+2x)​

Answer 1

STEP

1

:

Equation at the end of step 1

(4x•((xy+(2•(y2)))-3y))-((2•(y2))•((2x2+4xy)+2x))

STEP

2

:

Equation at the end of step

2

:

(4x•((xy+(2•(y2)))-3y))-(2y2•(2x2+4xy+2x))

STEP

3

:

STEP

4

:

Pulling out like terms

4.1 Pull out like factors :

2x2 + 4xy + 2x = 2x • (x + 2y + 1)

Multiplying exponents:

4.2 21 multiplied by 21 = 2(1 + 1) = 22

Equation at the end of step

4

:

(4x•((xy+(2•(y2)))-3y))-22xy2•(x+2y+1)

STEP

5

:

Equation at the end of step

5

:

(4x•((xy+2y2)-3y))-22xy2•(x+2y+1)

STEP

6

:

STEP

7

:

Pulling out like terms

7.1 Pull out like factors :

xy + 2y2 - 3y = y • (x + 2y - 3)

Equation at the end of step

7

:

4xy • (x + 2y - 3) - 22xy2 • (x + 2y + 1)

STEP 8:

Pulling out like terms

9.1 Pull out like factors :

-4x2y2 + 4x2y - 8xy3 + 4xy2 - 12xy =

-4xy • (xy - x + 2y2 - y + 3)

Final result :

-4xy • (xy - x + 2y2 - y + 3)

Explanation: