Question

What kinematics equation would i use for this ? Btw one of those are the answers

Answer 1

Given that the time taken to reach the ground is t = 6 s

The final velocity is v = 0m/s

We have to find the height of the monument, h.

The initial velocity can be calculated by the formula

`u=gt`

Here, g is the acceleration is due to gravity whose value is 9.81 m/s^2

Substituting the values, the initial velocity will be

`\begin{gathered} u=9.81*6 \\ =58.86\text{ m/s} \end{gathered}`

The formula to find height is

`h=(u^2)/(2g)`

Substituting the values, the height will be

`\begin{gathered} h=((58.86)^2)/(2*9.81) \\ =176.58 \\ \approx177\text{ m} \end{gathered}`

Thus, the correct option is 177 m.