Answer
H₂O₂ undergoes oxidation
KMnO₄ undergoes reduction
Step-by-step explanation
Given equation:
3H2SO4 + 2KMnO4 + 5H2O2 --> 5O2 + 2MnSO4 + 8H2O + K2SO4
The oxidation number of O in H₂O₂ is -1 and this changes to o in O₂ on the product side. Hence, H₂O₂ undergoes oxidation.
The oxidation number of Mn in KMnO₄ is +7 and changes to +2 in MnSO₄ on the product side. Therefore, KMnO₄ undergoes reduction.