Question

a Bismuth-210 has a half-life of about 5 days. After 17 days, how many milligrams of a 1,728 mg sample will remain? Round answer to the nearest tenth place. If answer does not have tenths place use a zero so that it does.

Answer 1

Explanation:

We have been given that Bismuth-210 has a half-life of about 5 days.

To solve our given problem we will use half-life formula.

`y=a*((1)/(2))^{(t)/(b)}`

Where,

a = Initial value,

t = Time,

b = half-life.

Given:

`\begin{gathered} a=1728mg \\ t=17 \\ b=5 \end{gathered}`

Therefore,

`y=1728((1)/(2))^{(17)/(5)}`

Simplify

`y=163.69738\approx163.7mg`

Hence, the answer is

`163.7mg`