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The difference between the roots of the quadratic equation x^2-10+q=0 is 6

The difference between the roots of the quadratic equation x^2-10+q=0 is 6-example-1
User Stirling
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2 Answers

19 votes
19 votes

Answer:

Explanation:

16

User AmagicalFishy
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15 votes
15 votes

Let the expression be written in form of a and b

the sum of a quadratic is the mid value -a/b which is equal to -(-10) /1,

Hence a + b = -( - 10 ) , a+b = 10 ------ ( 1 )

Next, recall, that the questions says the subtraction is 6.

Hence a - b = 6 ------ ( 2 )

finally, q is in the product position in the quadratic expression,

hence, ab = q ------- ( 3 )

Solving eqation 1 and 2 simultaneously

a + b = 10 ----- (1)

a - b = 6 -------(2)

2b = 10 - 6 ( subtractind equation 1 from 2 and eliminating a )

2b = 4

b= 4/2 ( dividing both sides by 2 )

b = 2

( Now, substitute the value b into equation 2 )

a - 2 = 6

a = 6 + 2

a = 8. ( generally a = 8 and b = 2 )

( now substitite your values a and b into equation 3 to find q )

ab = q

8 x 2 = q

Therefore the value of q is 16

User Dmkc
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