Question

25. Write the equation for lines 'a' and 'b'Line 'a':Line 'b'

Answer 1

As you can see, line a intersects the y axis at point ( 0, 1 ) and the x axis at point ( -2, 0).

Basically, the slope (m) is rise over run, that is, m = (y2 - y1) / (x2 - x1) = 0-1 / -2-0 = 1/2. And our y=intercept, b is 1 (since the line intersects that y axis at 1). Using the point slope form , y = mx +b, the equation of line a is:

`\begin{gathered} y=(1)/(2)x+1 \\ 2y=x+2 \\ x-2y+2=0 \end{gathered}`

As you can see, line b intersects the y axis at point ( 0, -2 ) and the x axis at point ( -1, 0).

Basically, the slope (m) is rise over run, that is, m = (y2 - y1) / (x2 - x1) = 0-(-2) / -1-0 = 2 / -1 = -2. And our y=intercept, b is -2 (since the line intersects that y axis at -2). Using the point slope form , y = mx +b, the equation of line a is:

`\begin{gathered} y=(-2)x+(-2) \\ y=-2x-2 \\ 2x+y+2=0 \end{gathered}`

Answer:

`\begin{gathered} a\colon x-2y+2=0 \\ b\colon2x+y+2=0 \end{gathered}`